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Attendance shortage alert

For each subject, show the attendance % and exactly how many more lectures a student must attend to reach 75%.

Skills: C / Python, arrays, arithmetic, loops

A common worry for every college student before exams

The problem

Students often realise too late that their attendance is below 75% in some subjects. A simple tool can warn them early and tell them how many lectures they must not miss.

For every subject you know the lectures held so far and the lectures attended. If a student attends every coming lecture, how many more do they need to reach 75%?

Example: held 40, attended 26 → 65%. Attending x more gives (26 + x) / (40 + x) ≥ 0.75 → x = 16.

Your solution should

01Read the number of subjects and, for each, its name, lectures held and lectures attended
02Reject attended > held
03Print the attendance % with one decimal place
04For subjects below 75%, print the number of continuous lectures needed
05For subjects at or above 75%, print how many lectures can be missed and still stay at 75%

Stuck? Show hints (3)

From (a + x) / (h + x) ≥ 0.75 you get x ≥ 3h − 4a
Lectures you can miss: the largest m with a / (h + m) ≥ 0.75, i.e. m = floor(a / 0.75) − h
Use integer arithmetic where you can to avoid rounding mistakes

Attendance shortage alert

The problem

Your solution should

Attendance shortage alert

The problem

Your solution should

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